C++/CLI中使用gcnew关键字表示在托管堆上分配内存，并且为了与以前的指针区分，用^来替换* ，就语义上来说他们的区别大致如下:
1. gcnew返回的是一个句柄(Handle)，而new返回的是实际的内存地址.
2. gcnew创建的对象由虚拟机托管，而new创建的对象必须自己来管理和释放.
当然，从程序员的角度来说，管它是句柄还是什么其他的东西，总跑不掉是对某块内存地址的引用，实际上我们都可以理解成指针.下面我们就写一段代码来测试一下好了.
using namespace System;
ref class Foo
{
public:
Foo()
{
System::Console::WriteLine("Foo::Foo");
}
~Foo()
{
System::Console::WriteLine("Foo::~Foo");
}
public:
int m_iValue;
};
int _tmain()
{
int* pInt = new int;
int^ rInt = gcnew int;
Foo^ rFoo = gcnew Foo;
delete rFoo;
delete rInt;
delete pInt;
}
我把调试的时候JIT编译的汇编代码择录了部分如下显示（请注意红色部分）：
int* pInt = new int;
0000004c mov ecx，4
00000051 call dword ptr ds:[03B51554h]
00000057 mov esi，eax
00000059 mov dword ptr [esp+18h]，esi
int^ rInt = gcnew int;
0000005d mov ecx，788EF9D8h
00000062 call FCFAF66C
00000067 mov esi，eax
00000069 mov dword ptr [esi+4]，0
00000070 mov edi，esi
Foo^ rFoo = gcnew Foo;
00000072 mov ecx，3B51768h
00000077 call FCFAF66C
0000007c mov esi，eax
0000007e mov ecx，esi
00000080 call dword ptr ds:[03B517ACh]
00000086 mov dword ptr [esp+1Ch]，esi
delete rFoo;
0000008a mov ebx，dword ptr [esp+1Ch]
0000008e test ebx，ebx
00000090 je 000000A4
00000092 mov ecx，ebx
00000094 call dword ptr ds:[03FD0028h]
0000009a mov dword ptr [esp+14h]，0
000000a2 jmp 000000AC
000000a4 mov dword ptr [esp+14h]，0
delete rInt;
000000ac mov edx，edi
000000ae mov ecx，788F747Ch
000000b3 call FC8D20FD
000000b8 mov ebp，eax
000000ba test ebp，ebp
000000bc je 000000D0
000000be mov ecx，ebp
000000c0 call dword ptr ds:[03FD0020h]
000000c6 mov dword ptr [esp+10h]，0
000000ce jmp 000000D8
000000d0 mov dword ptr [esp+10h]，0
delete pInt;
000000d8 mov ecx，dword ptr [esp+18h]
000000dc call dword ptr ds:[03B51540h]
