热门文章 | 热门软件| 热门源码 | 热门电影 | 知识库 | 联系我们
软件 源码 教程 影视 健康 招聘
  HTML | JavaScript | ASP | PHP | JSP | NET | VB | VC | VF | Windows | Linux | Mysql | Mssql | Oracle | Struts 
当前位置: 创世纪计算机资源网 -> 文章频道 ->struts 
站内搜索:
经典的Struts2+Spring 2+JPA+AJAX学习项目(3)
作者:佚名 来源:互联网 整理日期:2008-4-9

@PersistenceContext will make Spring inject an EntityManager into the service when it is instantiated. The @PersistenceContext annotation can be placed on the field, or on the setter method. If the class is annotated as @Transactional, Spring will make sure that its methods run inside a transaction.

JPA configuration

  1. Create a folder named "META-INF" under the "src" folder.
  2. Create a file named "persistence.xml" under the "META-INF" folder and set its content to:
persistence.xml
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence 
http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"
version="1.0"> <persistence-unit name="punit"> </persistence-unit> </persistence>

JPA configuration can be set on this file. On this example it will be empty because the datasource configuration will be on the Spring configuration file.

Spring

  1. Update the content of web.xml under /WebContent/WEB-INF/web.xml to:
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="person" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
    <display-name>person</display-name>
    <filter>
        <filter-name>struts2</filter-name>
        <filter-class>
            org.apache.struts2.dispatcher.FilterDispatcher
        </filter-class>
    </filter>

    <filter-mapping>
        <filter-name>struts2</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>


    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>

    <listener>
        <listener-class>
            org.springframework.web.context.ContextLoaderListener
        </listener-class>
    </listener>
</web-app>

This will make the container redirect all requests to Struts "FilterDispatcher" class. "index.jsp" is set as the home page, and Springs "ContextLoaderListener" is configured as a listener.

  1. Create a file named "applicationContext.xml" under /WebContent/WEB-INF, and set its content to:
applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:aop="http://www.springframework.org/schema/aop"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xsi:schemaLocation="
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
    http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.0.xsd
    http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.0.xsd">

    <bean
        class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />

    <bean id="personService" class="quickstart.service.PersonServiceImpl" />

    <bean id="entityManagerFactory"
        class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSource" />
        <property name="jpaVendorAdapter">
            <bean
                class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
                <property name="database" value="MYSQL" />
                <property name="showSql" value="true" />
            </bean>
        </property>
    </bean>

    <bean id="dataSource"
        class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="com.mysql.jdbc.Driver" />
        <property name="url" value="jdbc:mysql://localhost/quickstart" />
        <property name="username" value="root" />
        <property name="password" value="root" />
    </bean>

    <bean id="transactionManager"
        class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory" />
    </bean>

    <tx:annotation-driven transaction-manager="transactionManager" />

    <bean id="personAction" scope="prototype"
        class="quickstart.action.PersonAction">
        <constructor-arg ref="personService" />
    </bean>
</beans>

[1]  [2]  [3]  [4]  [5]  
相关文章